# countable

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## Synonyms for countable

### that can be counted

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There exists a countable set E in E such that A = [E.sup.[perpendicular to].sub.w] + A where,
Then there exists a countable set [D.sub.0] [subset] D, such that [alpha](D) [less than or equal to] 2[alpha]([D.sub.0]).
If X is a countable set, then a sequence [[mu].sub.n] converges strongly to a limit [mu] if and only if
Therefore, if f is replaced by [f.sup.**], the minimization problem involving [g.sub.[alpha]] gives the same solution, except possibly a countable set of values [alpha] where the maximum is attained (either for f or [f.sup.**]) in more than one point
(48a)-(48c), a countable set of other solutions exists for the frequency [??] = [eta].
Then by Lemma 1, there exists an open subset V containing x and a countable set C such that V - C [subset not equal to] sInt(B).
Then, the set of all discontinuity points of f is at most a countable set in R.
Let V = {[x.sub.1], [x.sub.2], [X.sub.3], ...} be a countable set of variables.
Then there exists a countable set of indices {[[alpha].sub.n]: n [member of] N} such that [MATHEMATICAL EXPRESSION NOT REPRODUCIBLE IN ASCII].
Using methods from linear functional analysis Conca, Planchard and Vanninathan [3] proved that this problem has a countable set of eigenvalues which are positive and real and which converge to infinity.
What is used is the corollary that every countable set of reals is representable in a constructible model.
We can assume without loss of generality f is one-to-one off of a countable set [St]; also, by [A13] and [P2] we know that f extends continuously to U.
Now, let us consider a countable set {[E.sub.i]} of subsets of diameter at most [epsilon] that covers W; that is,
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